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0=4x^2-484
We move all terms to the left:
0-(4x^2-484)=0
We add all the numbers together, and all the variables
-(4x^2-484)=0
We get rid of parentheses
-4x^2+484=0
a = -4; b = 0; c = +484;
Δ = b2-4ac
Δ = 02-4·(-4)·484
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7744}=88$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-88}{2*-4}=\frac{-88}{-8} =+11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+88}{2*-4}=\frac{88}{-8} =-11 $
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